United States presidential election in Louisiana, 1840
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Lua error in package.lua at line 80: module 'strict' not found. The 1840 United States presidential election in Louisiana took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for President and Vice President.
Louisiana voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won Louisiana by a margin of 19.46%.
Results
| United States presidential election in Louisiana, 1840[1] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Whig | William Henry Harrison of Ohio | John Tyler of Virginia | 11,296 | 59.73% | 5 | 100.00% | ||
| Democratic | Martin Van Buren of New York | Richard M. Johnson of Kentucky | 7,616 | 40.27% | 0 | 0.00% | ||
| Total | 18,912 | 100.00% | 5 | 100.00% | ||||
References
- ↑ Lua error in package.lua at line 80: module 'strict' not found.
| Candidates |
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| General articles |
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| Local results |
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| Other 1840 elections |
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