United States presidential election in Michigan, 1992

Main article: United States presidential election, 1992

United States presidential election in Michigan, 1992

November 3, 1992

Nominee Bill Clinton George H.W. Bush Ross Perot Party Democratic Republican Independent Home state Arkansas Texas Texas Running mate Al Gore Dan Quayle James Stockdale Electoral vote 18 0 0 Popular vote 1,871,182 1,554,940 824,813 Percentage 43.77% 36.38% 19.30%

350px County Results   Clinton—>70%   Clinton—60-70%   Clinton—50-60%   Clinton—40-50%   Bush—40-50%   Bush—50-60%   Bush—60-70%   Bush—>70%   Perot—40-50%

President before election George H. W. Bush Republican Elected President Bill Clinton Democratic

Clinton on campaign. Seen here with local Democratic notables in front of Rackham School at the University of Michigan in October, 1992.

The 1992 United States presidential election in Michigan took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose eighteen representatives, or electors to the Electoral College, who voted for President and Vice President.

Michigan was won by Governor Bill Clinton (D-Arkansas) with 43.77% of the popular vote over incumbent President George H.W. Bush (R-Texas) with 36.38%. Businessman Ross Perot (I-Texas) finished in third with 19.30% of the popular vote. Clinton ultimately won the national vote, defeating incumbent President Bush. This was the first time that a Democratic presidential candidate carried Michigan since 1968.

Results

United States presidential election in Michigan, 1992
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic	Bill Clinton	1,871,182	43.77%	18
	Republican	George H.W. Bush	1,554,940	36.38%	0
	Independent	Ross Perot	824,813	19.30%	0
	Libertarian	Andre Marrou	10,175	0.24%	0
	Taxpayers’	Howard Phillips	8,263	0.19%	0
	Natural Law	Dr. John Hagelin	2,954	0.07%	0
	Socialist Equality	Helen Halyard	1,432	0.03%	0
	Write-ins		914	0.02%	0
Totals			4,274,673	100.0%	18