United States presidential election in Wyoming, 2000

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United States presidential election in Wyoming, 2000

← 1996 November 7, 2000 2004 →
  George-W-Bush.jpeg Al Gore, Vice President of the United States, official portrait 1994.jpg
Nominee George W. Bush Al Gore
Party Republican Democratic
Home state Texas Tennessee
Running mate Dick Cheney Joe Lieberman
Electoral vote 3 0
Popular vote 147,947 60,481
Percentage 67.76% 27.70%

WY2000.jpg
County Results
  Bush—50-60%
  Bush—60-70%
  Bush—70-80%
  Bush—80-90%

President before election

Bill Clinton
Democratic

Elected President

George W. Bush
Republican

The 2000 United States presidential election in Wyoming took place on November 7, 2000 throughout all 50 states and D.C., which was part of the 2000 United States presidential election. Voters chose 3 representatives, or electors to the Electoral College, who voted for President and Vice President.

Wyoming was won by Governor George W. Bush by a massive 40.06% margin of victory.

Electors

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The electors of each state and the District of Columbia met on December 18, 2000[1] to cast their votes for President and Vice President. The Electoral College itself never meets as one body. Instead the electors from each state and the District of Columbia met in their respective capitols.

The following were the members of the Electoral College from the state. All were pledged to and voted for George Bush and Dick Cheney:[2]

  1. Judy Catchpole
  2. Gale Geringer
  3. John Patton

Results

United States presidential election in Wyoming, 2000[3]
Party Candidate Votes Percentage Electoral votes
Republican George W. Bush 147,947 67.76% 3
Democratic Al Gore 60,481 27.70% 0
Write-in Ralph Nader 4,625 2.12% 0
Reform Pat Buchanan 2,724 1.25% 0
Libertarian Harry Browne 1,443 0.66% 0

References

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See also

  1. http://uselectionatlas.org/RESULTS/state.php?year=2000&fips=56&f=0&off=0&elect=0
  2. http://presidentelect.org/e2000.html
  3. http://uselectionatlas.org/RESULTS/index.html